How do you find the inverse of $g (x) = y = {(x - 6)}^{5}$ $g(x) = y = (x-6)^5$ ?

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Answer 1 · 2018-05-02T12:46:53

$g^{- 1} (x) = x^{\frac{1}{5}} + 6$ $g^-1(x) = x^(1/5)+6$

$g (x) = y = {(x - 6)}^{5}$ $g(x)=y=(x-6)^5$ or

$y^{\frac{1}{5}} = (x - 6) or x = y^{\frac{1}{5}} + 6$ $y^(1/5)=(x-6) or x = y^(1/5)+6$ or

$g^{- 1} (y) = y^{\frac{1}{5}} + 6$ $g^-1(y) = y^(1/5)+6$ or

$g^{- 1} (x) = x^{\frac{1}{5}} + 6$ $g^-1(x) = x^(1/5)+6$ [Ans]

How do you find the inverse of g(x) = y = (x-6)^5g(x)=y=(x−6)5g(x) = y = (x-6)^5?