How do you find the inverse of #h(x)=(5x+1)/4#?
1 Answer
Jul 20, 2018
Explanation:
#"let "y=(5x+1)/4#
#"rearrange making x the subject"#
#5x+1=4y#
#5x=4y-1#
#x=(4y-1)/5#
#rArrf^-1(x)=(4x-1)/5#
