How do you find the inverse of #log(x)=3#?

1 Answer
Nov 18, 2016

Answer:

Please see the explanation.

Explanation:

I am assuming that the logarithm is base 10:

#log_10(x) = 3#

Make both sides of the equation an exponent of 10:

#10^(log_10(x)) = 10^3#

Use the property of logarithms, #b^(log_b(x)) = x#:

#x = 10^3#

#x = 1000#