Question

How do you find the inverse of `y= log_6 (x+2)`?

Answer 1

`x=6^y-2`

Explanation:

Start with the basic equivalence:
`color(white)("XXX")c=log_b a hArr a=b^c`

Therefore
`color(white)("XXX")y=log_6(x+2) hArr 6^y=x+2`

From which it follows that
`color(white)("XXX")6^y-2=x`