How do you find the LCM of #b+5, (b-5)^2# and #b^2-25#?

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Answer 1 · 2018-02-08T12:46:20

#(b + 5)^2(b-5)^3#

First factorise the expressions which can be factorised.

First Expression :- #b + 5#

Second Expression :- #(b-5)^2# = #(b-5)(b-5)#

Third Expression :- #b^2 - 25# = #(b)^2 - (5)^2# = #(b + 5)(b- 5)#

There is no common factor in all three expressions.

So the LCM will be the multiple of the three expressions.

So, LCM

= #(b+5)(b+5)(b-5)(b-5)(b-5)#

= #(b + 5)^2(b-5)^3#