How do you find the length of the curve y=3x-2, 0<=x<=4? Calculus Applications of Definite Integrals Determining the Length of a Curve 1 Answer James May 15, 2018 L=int_0^4sqrt[1+9]*dx=[sqrt10x]_0^4=4sqrt10 Explanation: show below y=3x-2 y'=3 L=int_a^bsqrt[1+(y')^2]*dx=int_0^4sqrt[1+9]*dx =[sqrt10x]_0^4=4sqrt10 Answer link Related questions How do you find the arc length of y=ln(cos(x)) on the interval [pi/6,pi/4]? What is arc length parametrization? How do you find the length of a curve defined parametrically? How do you find the length of a curve using integration? How do you find the length of a curve in calculus? How do you find the arc length of x=2/3(y-1)^(3/2) between 1<=y<=4? How do you find the length of the curve y=x^5/6+1/(10x^3) between 1<=x<=2 ? How do you find the length of the curve y=e^x between 0<=x<=1 ? How do I find the arc length of the curve y=ln(sec x) from (0,0) to (pi/ 4, ln(2)/2)? How do I find the arc length of the curve y=ln(cos(x)) over the interval [0,π/4]? See all questions in Determining the Length of a Curve Impact of this question 5827 views around the world You can reuse this answer Creative Commons License