How do you find the limit #(3x^2+x+2)/(x-4)# as #x->0#?
1 Answer
Nov 28, 2016
Explanation:
The function is neither undefined/indeterminate for x = 0. Hence we can evaluate the limit by substitution.
#lim_(xto0)((3x^2+x+2)/(x-4))=(0+0+2)/(0-4)=-1/2#
