How do you find the limit #lim 5^(x^2-2x+1)# as #x->3#?

1 Answer
Oct 12, 2017

Answer:

First thing to do is...

Explanation:

For these sorts of limit problems, the first thing to try is always just to substitute the value that x is approaching, and see what the function evaluates to. If it's defined and has a value at that point, then your work is done.

Here, if #x=3#, then #x^2-2x+1 = 9 - 6 + 1 = 4#

So you have #5^4 = 625#

GOOD LUCK