How do you find the limit #lim x^(-1/3)# as #x->-oo#?

1 Answer
May 13, 2018

Answer:

0

Explanation:

You can write #x^(-1/3)# as #1/root(3)(x)#

To think about the limit, think about this: what would happen to the fraction as #x# approaches infinitely large negative values? The 1 in the numerator will be divided by larger and larges values, so the fraction will become smaller and smaller and hence it will tend toward 0 (but not equal 0).

So the answer is 0. Hope this helps!