Question

How do you find the Limit of `-1` as `x->2` and then use the epsilon delta definition to prove that the limit is L?

Answer 1

As `x` approaches `-2` the value of `-1` does not change, it is `-1`, so the limit is `-1`

Explanation:

In this question `f(x) = -1`

Given `epsilon > 0`, choose `delta` equal to any positive number you like. I'll use `delta = 2`

Now for every `x`, if `0 < abs(x-(-2)) < delta`, then `abs(f(x)-(-1)) = abs(-1+1) = abs(0) = 0 < epsilon` as required by the definition.