# How do you find the limit of 1/(x^3 +4)  as x approaches infinity?

${\lim}_{\text{x->oo}} \frac{1}{{x}^{3} + 4} = 0$
${\lim}_{\text{x->oo" 1/(x^3+4) = lim_"x->oo}} \frac{\frac{1}{x} ^ 3}{1 + \frac{4}{x} ^ 3}$
$= \frac{0}{1 + 0} = 0$