How do you find the limit of # 1 / (x-3)# as x approaches 3?
1 Answer
Apr 28, 2016
Explanation:
Given,
#lim_(xrarr3)1/(x-3)#
Substitute
#=lim_(xrarr3)1/(3-3)#
#=lim_(xrarr3)1/0#
Since you cannot divide a value by
#=# does not exist (D.N.E.)