# How do you find the limit of (2x^2 + 1) /( (2-x)(2+x)) as x approaches infinity?

Jul 12, 2016

${\lim}_{x \to \infty} \frac{2 {x}^{2} + 1}{\left(2 - x\right) \left(2 + x\right)} = - 2$
${\lim}_{x \to \infty} \frac{2 {x}^{2} + 1}{4 - {x}^{2}}$
${\lim}_{x \to \infty} \frac{2 + \frac{1}{x} ^ 2}{\frac{4}{x} ^ 2 - 1} = \frac{2 + 0}{0 - 1} = - 2$