How do you find the limit of #2x+5# as #x->7^-#? Calculus Limits Determining One Sided Limits 1 Answer Steve M Oct 27, 2016 # lim_(x->7^-)(2x+5) =19 # Explanation: #2x+5# is continuous; so So, # lim_(x->7^-)(2x+5) = lim_(x->7^+)(2x+5) = lim_(x->7)(2x+5) # Hence, # lim_(x->7^-)(2x+5) =2(7)+5=19 # Answer link Related questions When is a one sided limit undefined? How do you find a one sided limit for an absolute value function? How do you find the limit #lim_(x->3^+)|3-x|/(x^2-2x-3)# ? How do you find the limit #lim_(x->2^+)sqrt(2-x)# ? How do you find the limit #lim_(x->0^-)|x|/x# ? How do you find the limit as x approaches 2 of the piecewise function #f(x)={(4-x^2,if... How do you find the limit of the piecewise function #f(x)={(x^2,if x text{ is rational}),(0,if... How do you find one sided limits without graph? How do you find one sided limits algebraically? How do you determine one sided limits numerically? See all questions in Determining One Sided Limits Impact of this question 4574 views around the world You can reuse this answer Creative Commons License