Question

How do you find the limit of `(4x-5x^2)/(x-1)` as `x->0`?

Answer 1

`0`

Explanation:

For this we can just plug zero in `(4x-5x^2)/(x-1)`

`(4(0)-5(0)^2)/((0)-1)=0`

`:.`

`lim_(x->0)(4x-5x^2)/(x-1)=0`