Question

How do you find the limit of `(costhetatantheta)/theta` as `theta->0`?

Answer 1

Use `tan theta = sintheta/costheta`

Explanation:

`lim_(thetararr0)(costheta tantheta)/theta = lim_(thetararr0)(costheta ((sintheta)/costheta))/theta`

`= lim_(thetararr0)sintheta/theta = 1`