How do you find the limit of #e^(-3x)# as x approaches infinity? Calculus Limits Infinite Limits and Vertical Asymptotes 1 Answer Jim H Apr 17, 2015 #e^(-3x) = 1/(e^(3x))# As #x rarr oo#, the denominator #e^(3x) rarr oo#, so the expression: #e^(-3x) = 1/(e^(3x)) rarr 0# Answer link Related questions How do you show that a function has a vertical asymptote? What kind of functions have vertical asymptotes? How do you find a vertical asymptote for y = sec(x)? How do you find a vertical asymptote for y = cot(x)? How do you find a vertical asymptote for y = csc(x)? How do you find a vertical asymptote for f(x) = tan(x)? How do you find a vertical asymptote for a rational function? How do you find a vertical asymptote for f(x) = ln(x)? What is a Vertical Asymptote? How do you find the vertical asymptote of a logarithmic function? See all questions in Infinite Limits and Vertical Asymptotes Impact of this question 9588 views around the world You can reuse this answer Creative Commons License