Question

How do you find the limit of `e^(x^2-x)` as x approaches 1?

Answer 1

See below.

Explanation:

For: `e^(x^2-x)`

All you need to do to solve this is plug in 1 for `x`:

Then:

`e^(1^2-1)=> e^0=1`

So:

`lim_(x->1)(e^(x^2-1))=1`