Question

How do you find the limit of `sin(2x-sin(5x))` as x approaches pi?

Answer 1

0

Explanation:

`lim_( x to pi) sin(2x-sin(5x))`

Sine is a continuous function so we can just plug in the value of x

`lim_( x to pi) sin(2x-sin(5x))`

`= sin(2 pi-sin(5*pi)) = 0`