How do you find the limit of # (sin^4 x)/(x^4)# as x approaches 0?
1 Answer
May 30, 2016
Explanation:
A very important limit is that:
#lim_(xrarr0)sinx/x=1#
Thus,
#lim_(xrarr0)sin^4x/x^4=lim_(xrarr0)(sinx/x)^4=(lim_(xrarr0)sinx/x)^4=1^4=1#
Note that we used the rule
#lim_(xrarra)(f(x))^n=(lim_(xrarra)f(x))^n#