# How do you find the limit of #sin((x-1)/(2+x^2)) # as x approaches infinity?

##### 1 Answer

Dec 8, 2016

#### Explanation:

Because

#=sin(lim_(x->oo)(1/x-1/x^2)/(2/x^2+1))#

#=sin((0-0)/(0+1))#

#=sin(0)#

#=0#