Question

How do you find the limit of `sin(x+4sinx)` as x approaches pi?

Answer 1

`lim_(x->pi) sin(x + 4sinx) = sin(pi + 4sinpi)`

we know that `color(red)(sinpi = 0)`
thus we have:

`= sin(pi + 4(0))`
`= sinpi`
`=0`