Question

How do you find the limit of `(sin2x)/x` as x approaches infinity?

Answer 1

`=0`

Explanation:

`sin 2x` is a continuous periodic function bounded as `sin 2x in [-1,1]`

therefore

`lim_(x to oo) (sin 2x)/x`

`= lim_(x to oo) c/x` with `c in [-1,1]`

`=0`