Question

How do you find the limit of `sinx / x` as x approaches infinity?

Answer 1

0

Explanation:

`lim_{x \to oo} sinx / x`

we know that `sin x \in [-1,1], qquad forall x`, ie it is a bounded function

so we can re-write the limit as

`sinx * \ lim_{x \to oo} 1 / x = sin x * 0 = 0`