Question

How do you find the limit of `sqrt(4x^2-1) / x^2` as x approaches infinity?

Answer 1

It is

#lim_(x->oo) sqrt(4x^2-1) / x^2=lim_(x->oo) [absx*sqrt(4-1/x^2)]/[x^2]= lim_(x->oo) sqrt(4-1/x^2)*lim_(x->oo) 1/x=4*0=0#