# How do you find the lim_(x to 3) sqrt(x+1)/(x-4)?

Apr 19, 2018

The limit is the expression evaluated at 3.

#### Explanation:

${\lim}_{x \to 3} \frac{\sqrt{x + 1}}{x - 4} = \frac{\sqrt{3 + 1}}{3 - 4}$

${\lim}_{x \to 3} \frac{\sqrt{x + 1}}{x - 4} = \frac{\sqrt{4}}{-} 1$

${\lim}_{x \to 3} \frac{\sqrt{x + 1}}{x - 4} = \frac{2}{-} 1$

${\lim}_{x \to 3} \frac{\sqrt{x + 1}}{x - 4} = - 2$