# How do you find the limit of sqrt((x^2)+9x-8)+x as x approaches infinity?

${\lim}_{x \rightarrow \infty} \left(\sqrt{{x}^{2} + 9 x - 8} + x\right) = \infty$
As $x$ increases without bound, so also does $\sqrt{{x}^{2} + 9 x - 8}$.