Question

How do you find the limit of `(x^2+x-12)/(x-3)` as `x->-4`?

Answer 1

Substitution.

Explanation:

`lim_(xrarr-4)(x^2+x-12) = 16+(-4)-12 = 0`

`lim_(xrarr-4)(x-3) = -7`

So,

`lim_(xrarr-4)(x^2+x-12)/(x-3) = 0/(-7) = 0`