Question

How do you find the limit of `(X^2 – x – 6) / (X^2 – 5x + 6)` as x approaches 0?

Answer 1

As `xrarr0`, the denominator approaches `6`. The form is not indeterminate.

Explanation:

As `xrarr0`, the numerator approaches `-6`.

So,

`lim_(xrarr0)(x^2-5-6)/(x^2-5x+6) = (-6)/6 = -1`