Question

How do you find the limit of `(x-3)/(x^2+4)` as `x->1`?

Answer 1

`lim_{x rarr 1} {x-3}/{x^2 + 4} = - 2/5`

Explanation:

When we have not any indeterminate form and limit exists, the value of a limit `lim_{x rarr a} f(x)` it's just `f (a)`. It means that:

`lim_{x rarr 1} {x - 3}/{x^2 + 4} = {1 - 3}/{1^2 + 4} = - 2/5`.