Question

How do you find the limit of `(x+sinx)/(2x-sinx)` as x approaches infinity?

Answer 1

`lim_{x->infty}(x+sin(x))/(2x-sin(x)) = 1/2`

Explanation:

`lim_{x->infty}(x+sin(x))/(2x-sin(x)) = lim_{x->infty}(1+sin(x)/x)/(2-sin(x)/x) = 1/2`