How do you find the line to the tangent to the curve #y=1+x+x^2+x^3# at the point (1,4)?
1 Answer
Sep 27, 2017
Explanation:
#•color(white)(x)m_(color(red)"tangent")=dy/dx#
#dy/dx=1+2x+3x^2#
#"at the point "(1,4)#
#dy/dx=1+2+3=6=m_(color(red)"tangent")#
#"expressing the tangent line in point-slope form"#
#y-4=6(x-1)#
#rArry-4=6x-6#
#rArry=6x-2larrcolor(red)" in slope-intercept form"#
