Question

How do you find the linearization at a=0 of `f(x) =sqrt(25-x)`?

Answer 1

`L(x) = f(a)+f'(a)(x-a)`

Explanation:

Here we have `f(0) = 5`, and

`f'(x) = -1/(2sqrt(25-x))`, so `f'(0) = -1/10`

Therefore,

`L(x) = 5-1/10x`