How do you find the Maclaurin series of f(x)=cos(x^2) ?

Sep 12, 2014

We have the Maclaurin series
cosx=sum_{n=0}^infty(-1)^n{x^{2n}}/{(2n)!}

by replacing $x$ by ${x}^{2}$,
cos(x^2)=sum_{n=0}^infty(-1)^n{x^{4n}}/{(2n)!}