How do you find the maximum value of #f(x) = -3x^2 +30x -50#?
1 Answer
Aug 26, 2017
Maximum value of
Explanation:
At
Stationary point is
2nd derivative test for maximum or minimum :
If
So
graph{-3x^2+30x-50 [-50.64, 50.6, -25.28, 25.37]} [Ans]