# How do you find the maximum value of #f(x) = -3x^2 +30x -50#?

##### 1 Answer

Aug 26, 2017

**Maximum value of**

#### Explanation:

At

Stationary point is

2nd derivative test for maximum or minimum :

If

So

graph{-3x^2+30x-50 [-50.64, 50.6, -25.28, 25.37]} [Ans]