How do you find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12?

1 Answer
May 9, 2018

Answer:

#/_A=32^@, /_B=64^@, /_C=84^@#

Explanation:

To be certain I understand your question correctly, you have a triangle, where you with "measures" mean number of degrees each angle is.

I.e. let the triangle look something like this:

enter image source here

If #/_A=a^@#
Then #/_B=2/_A=2a^@#
And #/_C=3/_A-12^@=3a^@-12^@#

If my understanding of your question is correct, we have
#/_A+/_B+/_C=180^@#
Therefore #a^@+2a^@+3a^@-12^@=180^@#

This gives #6a^@-12^@=180^@#
Or #a^@=32^@#

The angles in the triangle, therefore, are
I.e. #/_A=a^@=32^@#
Then #/_B=2/_A=2a^@=64^@#
And #/_C=3/_A-12^@=84^@#

This gives the following triangle:

enter image source here