How do you find the missing value to create a perfect square trinomial for #x^2+8x#?
1 Answer
Jul 6, 2018
Explanation:
#(x+a)^2=x^2+2ax+a^2#
#"compare with "x^2+8x#
#2a=8rArra=8/2=4#
#"hence "x^2+8x+4^2=x^2+8xcolor(red)(+16)=(x+4)^2#
