How do you find the nth term formula 4, 4.3, 4.6, 4.9?

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How do you find the nth term formula 4, 4.3, 4.6, 4.9?

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Answer 1 · 2016-07-01T10:24:38

$a_{n} = 4 + 0.3 (n - 1)$ $a_n=4+0.3(n-1)$

Explanation:

The difference between each term is 0.3 so we have an arithmetic sequence.

Let $i$ $i$ be the term position count in the sequence
Let any term be $a_{i}$ $a_i$

Then
$i \to a_{1} = 4$ $i->a_1=4$
$i \to a_{2} = 4 + 0.3$ $i->a_2=4+0.3$
$i \to a_{3} = 4.6 = 4 + (2 \times 0.3)$ $i->a_3=4.6=4+(2xx0.3)$
$i \to a_{4} = 4.9 = 4 + (3 \times 0.3)$ $i->a_4=4.9=4+(3xx0.3)$

We observe that any term $a_{i} = 4 + [(i - 1) \times 0.3]$ $a_i = 4+[(i-1)xx0.3]$

Thus for $i = n$ $i=n$ we have $a_{n} = 4 + [(n - 1) \times 0.3]$ $a_n=4+[(n-1)xx0.3]$

Write as: $a_{n} = 4 + 0.3 (n - 1)$ $" "a_n=4+0.3(n-1)$

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How do you find the nth term formula 4, 4.3, 4.6, 4.9?

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