How do you find the number of molecules equal to 1.46 moles of #CaCl_2#?

1 Answer
Mar 20, 2017

Answer:

There are #8.7892xx10^23# molecules in #1.46# mols of #CaCl_"2"#.

Explanation:

The formula we are using to convert is #n=N/N_"A"#.
=> Where #n# is the amount of moles, in mols.
=> Where #N# is the number of molecules.
=> Where #N_"A"# is Avogadro's Number. It is a constant number of #6.02 xx 10^23 "molecules"/"mol"#.

All we have to do is rearrange our equation to give us the amount of molecules, and plug in our numbers.

#n=N/N_"A"#

#N=n*N_"A"#

Now we plug in our variables.

#N=n*N_"A"#

#=1.46*(6.02 xx 10^23)#

#=8.7892xx10^23#

Therefore, there are #8.7892xx10^23# molecules in #1.46# mols of #CaCl_"2"#.

Hope this helps :)