Question

How do you find the number of molecules equal to 1.46 moles of `CaCl_2`?

Answer 1

There are `8.7892xx10^23` molecules in `1.46` mols of `CaCl_"2"`.

Explanation:

The formula we are using to convert is `n=N/N_"A"`.
=> Where `n` is the amount of moles, in mols.
=> Where `N` is the number of molecules.
=> Where `N_"A"` is Avogadro's Number. It is a constant number of `6.02 xx 10^23 "molecules"/"mol"`.

All we have to do is rearrange our equation to give us the amount of molecules, and plug in our numbers.

`n=N/N_"A"`

`N=n*N_"A"`

Now we plug in our variables.

`N=n*N_"A"`

`=1.46*(6.02 xx 10^23)`

`=8.7892xx10^23`

Therefore, there are `8.7892xx10^23` molecules in `1.46` mols of `CaCl_"2"`.

Hope this helps :)