# How do you find the number of solutions using the discriminant?

Apr 21, 2018

For $a {x}^{2} + b x + c = 0$, the values of $x$ which are the solutions to the equation are given by:
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
The discriminate is the portion of the quadratic equation within the radical: ${\textcolor{b l u e}{b}}^{2} - 4 \textcolor{red}{a} \textcolor{g r e e n}{c}$