How do you find the percent composition of all elements in sulfur trioxide?

1 Answer
Mar 20, 2017

Answer:

Well it is simply the quotient, #"mass of component"/"molar mass of compound"xx100%#

Explanation:

And #%S=(32.06*g*mol^-1)/(32.06*g*mol^-1+3xx16.00*g*mol^-1)xx100%#

#=40%#

And what must be #%O# given #%S#?

From where did I get the atomic masses in #g*mol^-1#? Did I simply know them off the top of my head?