How do you find the percent composition of oxygen in sodium hydroxide?

1 Answer
Meave60
Mar 21, 2017

The percent composition of oxygen in sodium hydroxide is #40.000%#.

Explanation:

Determine the molar mass of sodium hydroxide #("NaOH")#. Then divide the molar mass of oxygen by the molar mass of #"NaOH"#, and multiply by 100.

Molar Masses

#"NaOH":##"39.997 g/mol"#
https://www.ncbi.nlm.nih.gov/pccompound?term=NaOH

#"O":##"15.999 g/mol"# (periodic table)

Percent Composition of Oxygen

#"percent composition"=(15.999cancel("g"/"mol"))/(39.997cancel("g"/"mol"))xx100="40.000%"#

Related questions
See all questions in Percent Composition
Impact of this question
24131 views around the world
You can reuse this answer
Creative Commons License