# How do you find the perimeter of a rectangular object which has a length of sqrt128 feet and a width of sqrt200 feet?

Oct 5, 2015

Perimeter of the object is equal to $36 \sqrt{2}$ feet.
Length: $l = \sqrt{128} = \sqrt{64 \cdot 2} = 8 \sqrt{2}$
Width: $w = \sqrt{200} = \sqrt{100 \cdot 2} = 10 \sqrt{2}$
Perimeter: $p = 2 \left(w + l\right) = 2 \cdot \left(8 \sqrt{2} + 10 \sqrt{2}\right) = 2 \cdot 18 \sqrt{2} = 36 \sqrt{2}$