Question

How do you find the perimeter of a rectangular object which has a length of `sqrt128` feet and a width of `sqrt200` feet?

Answer 1

Perimeter of the object is equal to `36sqrt(2)` feet.

Explanation:

Length: `l=sqrt(128)=sqrt(64*2)=8sqrt(2)`

Width: `w=sqrt(200)=sqrt(100*2)=10sqrt(2)`

Perimeter: `p=2(w+l)=2*(8sqrt(2)+10sqrt(2))=2*18sqrt(2)=36sqrt(2)`