# How do you find the perimeter of an isosceles triangle whose base is 16 cm and whose height is 15 cm?

$P = 50 c m$

#### Explanation:

If the base is 16cm, the half base is $\frac{16}{2} = 8 c m$
(see figure below)

According to Pythagorean Theorem,
the other sides of the triangle are:

${a}^{2} = {8}^{2} + {15}^{2}$

${a}^{2} = 289$

$a = \sqrt{289} = 17$

The perimeter is:

$P = 16 + 17 + 17 = 50 c m$