How do you find the period of #2sin(2x) +1#?

1 Answer
Jan 31, 2018

#"period "=pi(180^@)#

Explanation:

#"the standard form of the sine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "a=2,b=2,c=0,d=1#

#rArr"period "=(2pi)/2=pi#