Question

How do you find the point-slope form of the equation of the line passing through the point (6, -3) and has a slope of 1/2?

Answer 1

The generic equation for the point-slope form is `y-y_1=m(x-x_1)`, where `m` is the slope, and `x_1` and `y_1` are the `x` and `y` values corresponding to the point given.

Slope: `m=1/2`
Point: `(6,-3)`
`x_1=6`
`y=-3`

`y-y_1=m(x-x_1)` =

`y-(-3)=1/2(x-6)`

`y+3=1/2x-3`