# How do you find the point-slope form of the equation of the line passing through the point (6, -3) and has a slope of 1/2?

May 28, 2015

The generic equation for the point-slope form is $y - {y}_{1} = m \left(x - {x}_{1}\right)$, where $m$ is the slope, and ${x}_{1}$ and ${y}_{1}$ are the $x$ and $y$ values corresponding to the point given.

Slope: $m = \frac{1}{2}$
Point: $\left(6 , - 3\right)$
${x}_{1} = 6$
$y = - 3$

$y - {y}_{1} = m \left(x - {x}_{1}\right)$ =

$y - \left(- 3\right) = \frac{1}{2} \left(x - 6\right)$

$y + 3 = \frac{1}{2} x - 3$