# How do you find the points of continuity for #f(x)=(x-4)/(x^2-16)#?

##### 1 Answer

May 27, 2015

Apparently this function has two points of discontinuity for

One of these two values, however, can be eliminated considering that:

So that only

Graphically:

graph{(x-4)/(x^2-16) [-16.02, 16.02, -8.01, 8.01]}