How do you find the points where the graph of the function #y= x +sinx# has horizontal tangents?

1 Answer
Mar 11, 2016

The tangent line is horizontal if and only if the slope of the tangetn line is #0#. And the slope of the tangent line is given by the derivative.

Explanation:

So, find the derivative, set it equal to #0#, and solve the resulting equation.

#y=x+sinx#

#y'=1+cosx#

#1+cosx = 0#
if and only if

#x=pi+2pik# for integer #k#.

(In words, these are the odd multiples of #pi#. They can be written #x=(2k+1)pi# for integer #k#.)

Because the sine of every such #x# is #0#, the #y# value at these point is

#y = (pi+2pik) + sin(pi+2pik) = pi+2pik# for integer #k#.

The points on the graph are: #(pi+2pik,pi+2pik)#

To help form an image of the solution above, here is the graph of the function.
(You can zoom in/out and drag the graph around to explore it a bit.)

graph{x+sinx [-25.52, 25.82, -15.62, 10.04]}