Question

How do you find the polar coordinate for ( 1/3 , 1/4 )?

Answer 1

Find the magnitude and the angle `theta`.

Explanation:

Magnitude `=sqrt((1/3)^2+(1/4)^2)=5/12`

`theta=tan^-1((1/4)/(1/3))=36.87^o`

polar `=(5/12,36.87^o)`