# How do you find the polar coordinates of the point with rectangular coordinates (-2,2 )?

The rectangular coordinates $\left(x , y\right) = \left(- 2 , 2\right)$ are $\left(r , \theta\right) = \left(2 \sqrt{2} , \frac{3 \pi}{4}\right)$ in polar coordinates.
Since $r$ is the distance of the point from the origin,
$r - \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{\left(- 2\right)}^{2} + {2}^{2}} = \sqrt{8} = 2 \sqrt{2}$
Since the positive x-axis and the segment connecting the origin and the point make ${135}^{\circ} = \frac{3 \pi}{4}$ rad,
$\theta = \frac{3 \pi}{4}$