How do you find the polar coordinates of the point with rectangular coordinates $(-2,2$ )?

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Answer 1 · 2014-09-19T11:40:37

The rectangular coordinates $(x,y)=(-2,2)$ are $(r,theta)=(2sqrt{2},{3pi}/4)$ in polar coordinates.

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Since $r$ is the distance of the point from the origin,

$r-sqrt{x^2+y^2}=sqrt{(-2)^2+2^2}=sqrt{8}=2sqrt{2}$

Since the positive x-axis and the segment connecting the origin and the point make $135^circ={3pi}/4$ rad,

$theta={3pi}/4$

How do you find the polar coordinates of the point with rectangular coordinates (-2,2(-2,2 )?